\(\int \frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{(2+3 x)^4} \, dx\) [2356]

Optimal result

Integrand size = 26, antiderivative size = 171 \[ \int \frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{(2+3 x)^4} \, dx=-\frac {39745 \sqrt {1-2 x} \sqrt {3+5 x}}{4536}+\frac {331 \sqrt {1-2 x} (3+5 x)^{3/2}}{168 (2+3 x)}-\frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{9 (2+3 x)^3}+\frac {181 \sqrt {1-2 x} (3+5 x)^{5/2}}{108 (2+3 x)^2}-\frac {575}{243} \sqrt {10} \arcsin \left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )-\frac {326717 \arctan \left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right )}{13608 \sqrt {7}} \]

[Out]

-1/9*(1-2*x)^(3/2)*(3+5*x)^(5/2)/(2+3*x)^3-326717/95256*arctan(1/7*(1-2*x)^(1/2)*7^(1/2)/(3+5*x)^(1/2))*7^(1/2
)-575/243*arcsin(1/11*22^(1/2)*(3+5*x)^(1/2))*10^(1/2)+331/168*(3+5*x)^(3/2)*(1-2*x)^(1/2)/(2+3*x)+181/108*(3+
5*x)^(5/2)*(1-2*x)^(1/2)/(2+3*x)^2-39745/4536*(1-2*x)^(1/2)*(3+5*x)^(1/2)

Rubi [A] (verified)

Time = 0.05 (sec) , antiderivative size = 171, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.308, Rules used = {99, 154, 159, 163, 56, 222, 95, 210} \[ \int \frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{(2+3 x)^4} \, dx=-\frac {575}{243} \sqrt {10} \arcsin \left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )-\frac {326717 \arctan \left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right )}{13608 \sqrt {7}}+\frac {181 \sqrt {1-2 x} (5 x+3)^{5/2}}{108 (3 x+2)^2}-\frac {(1-2 x)^{3/2} (5 x+3)^{5/2}}{9 (3 x+2)^3}+\frac {331 \sqrt {1-2 x} (5 x+3)^{3/2}}{168 (3 x+2)}-\frac {39745 \sqrt {1-2 x} \sqrt {5 x+3}}{4536} \]

[In]

Int[((1 - 2*x)^(3/2)*(3 + 5*x)^(5/2))/(2 + 3*x)^4,x]

[Out]

(-39745*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/4536 + (331*Sqrt[1 - 2*x]*(3 + 5*x)^(3/2))/(168*(2 + 3*x)) - ((1 - 2*x)^(
3/2)*(3 + 5*x)^(5/2))/(9*(2 + 3*x)^3) + (181*Sqrt[1 - 2*x]*(3 + 5*x)^(5/2))/(108*(2 + 3*x)^2) - (575*Sqrt[10]*
ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]])/243 - (326717*ArcTan[Sqrt[1 - 2*x]/(Sqrt[7]*Sqrt[3 + 5*x])])/(13608*Sqrt[7])

Rule 56

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]), x_Symbol] :> Dist[2/Sqrt[b], Subst[Int[1/Sqrt[b*c -
a*d + d*x^2], x], x, Sqrt[a + b*x]], x] /; FreeQ[{a, b, c, d}, x] && GtQ[b*c - a*d, 0] && GtQ[b, 0]

Rule 95

Int[(((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_))/((e_.) + (f_.)*(x_)), x_Symbol] :> With[{q = Denomin
ator[m]}, Dist[q, Subst[Int[x^(q*(m + 1) - 1)/(b*e - a*f - (d*e - c*f)*x^q), x], x, (a + b*x)^(1/q)/(c + d*x)^
(1/q)], x]] /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[m + n + 1, 0] && RationalQ[n] && LtQ[-1, m, 0] && SimplerQ[
a + b*x, c + d*x]

Rule 99

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(a + b*
x)^(m + 1)*(c + d*x)^n*((e + f*x)^p/(b*(m + 1))), x] - Dist[1/(b*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n
- 1)*(e + f*x)^(p - 1)*Simp[d*e*n + c*f*p + d*f*(n + p)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f}, x] && LtQ[m
, -1] && GtQ[n, 0] && GtQ[p, 0] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p] || IntegersQ[p, m + n])

Rule 154

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + d*x)^n*((e + f*x)^(p + 1)/(b*(b*e - a*f)*(m + 1))), x] - Dist[1
/(b*(b*e - a*f)*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[b*c*(f*g - e*h)*(m + 1) + (
b*g - a*h)*(d*e*n + c*f*(p + 1)) + d*(b*(f*g - e*h)*(m + 1) + f*(b*g - a*h)*(n + p + 1))*x, x], x], x] /; Free
Q[{a, b, c, d, e, f, g, h, p}, x] && ILtQ[m, -1] && GtQ[n, 0]

Rule 159

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[h*(a + b*x)^m*(c + d*x)^(n + 1)*((e + f*x)^(p + 1)/(d*f*(m + n + p + 2))), x] + Dist[1/(d*f*(m + n
+ p + 2)), Int[(a + b*x)^(m - 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*g*(m + n + p + 2) - h*(b*c*e*m + a*(d*e*(
n + 1) + c*f*(p + 1))) + (b*d*f*g*(m + n + p + 2) + h*(a*d*f*m - b*(d*e*(m + n + 1) + c*f*(m + p + 1))))*x, x]
, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && GtQ[m, 0] && NeQ[m + n + p + 2, 0] && IntegersQ[2*m, 2
*n, 2*p]

Rule 163

Int[(((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)))/((a_.) + (b_.)*(x_)), x_Symbol]
:> Dist[h/b, Int[(c + d*x)^n*(e + f*x)^p, x], x] + Dist[(b*g - a*h)/b, Int[(c + d*x)^n*((e + f*x)^p/(a + b*x)
), x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x]

Rule 210

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^(-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])
], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 222

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[Rt[-b, 2]*(x/Sqrt[a])]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rubi steps \begin{align*} \text {integral}& = -\frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{9 (2+3 x)^3}+\frac {1}{9} \int \frac {\left (\frac {7}{2}-40 x\right ) \sqrt {1-2 x} (3+5 x)^{3/2}}{(2+3 x)^3} \, dx \\ & = -\frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{9 (2+3 x)^3}+\frac {181 \sqrt {1-2 x} (3+5 x)^{5/2}}{108 (2+3 x)^2}-\frac {1}{54} \int \frac {\left (\frac {139}{4}-1065 x\right ) (3+5 x)^{3/2}}{\sqrt {1-2 x} (2+3 x)^2} \, dx \\ & = \frac {331 \sqrt {1-2 x} (3+5 x)^{3/2}}{168 (2+3 x)}-\frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{9 (2+3 x)^3}+\frac {181 \sqrt {1-2 x} (3+5 x)^{5/2}}{108 (2+3 x)^2}-\frac {\int \frac {\left (\frac {8757}{8}-\frac {119235 x}{2}\right ) \sqrt {3+5 x}}{\sqrt {1-2 x} (2+3 x)} \, dx}{1134} \\ & = -\frac {39745 \sqrt {1-2 x} \sqrt {3+5 x}}{4536}+\frac {331 \sqrt {1-2 x} (3+5 x)^{3/2}}{168 (2+3 x)}-\frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{9 (2+3 x)^3}+\frac {181 \sqrt {1-2 x} (3+5 x)^{5/2}}{108 (2+3 x)^2}+\frac {\int \frac {-\frac {317283}{4}-241500 x}{\sqrt {1-2 x} (2+3 x) \sqrt {3+5 x}} \, dx}{6804} \\ & = -\frac {39745 \sqrt {1-2 x} \sqrt {3+5 x}}{4536}+\frac {331 \sqrt {1-2 x} (3+5 x)^{3/2}}{168 (2+3 x)}-\frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{9 (2+3 x)^3}+\frac {181 \sqrt {1-2 x} (3+5 x)^{5/2}}{108 (2+3 x)^2}-\frac {2875}{243} \int \frac {1}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx+\frac {326717 \int \frac {1}{\sqrt {1-2 x} (2+3 x) \sqrt {3+5 x}} \, dx}{27216} \\ & = -\frac {39745 \sqrt {1-2 x} \sqrt {3+5 x}}{4536}+\frac {331 \sqrt {1-2 x} (3+5 x)^{3/2}}{168 (2+3 x)}-\frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{9 (2+3 x)^3}+\frac {181 \sqrt {1-2 x} (3+5 x)^{5/2}}{108 (2+3 x)^2}+\frac {326717 \text {Subst}\left (\int \frac {1}{-7-x^2} \, dx,x,\frac {\sqrt {1-2 x}}{\sqrt {3+5 x}}\right )}{13608}-\frac {1}{243} \left (1150 \sqrt {5}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {11-2 x^2}} \, dx,x,\sqrt {3+5 x}\right ) \\ & = -\frac {39745 \sqrt {1-2 x} \sqrt {3+5 x}}{4536}+\frac {331 \sqrt {1-2 x} (3+5 x)^{3/2}}{168 (2+3 x)}-\frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{9 (2+3 x)^3}+\frac {181 \sqrt {1-2 x} (3+5 x)^{5/2}}{108 (2+3 x)^2}-\frac {575}{243} \sqrt {10} \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )-\frac {326717 \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right )}{13608 \sqrt {7}} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.31 (sec) , antiderivative size = 108, normalized size of antiderivative = 0.63 \[ \int \frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{(2+3 x)^4} \, dx=\frac {-\frac {21 \sqrt {1-2 x} \sqrt {3+5 x} \left (78416+275022 x+286791 x^2+75600 x^3\right )}{(2+3 x)^3}+225400 \sqrt {10} \arctan \left (\frac {\sqrt {\frac {5}{2}-5 x}}{\sqrt {3+5 x}}\right )-326717 \sqrt {7} \arctan \left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right )}{95256} \]

[In]

Integrate[((1 - 2*x)^(3/2)*(3 + 5*x)^(5/2))/(2 + 3*x)^4,x]

[Out]

((-21*Sqrt[1 - 2*x]*Sqrt[3 + 5*x]*(78416 + 275022*x + 286791*x^2 + 75600*x^3))/(2 + 3*x)^3 + 225400*Sqrt[10]*A
rcTan[Sqrt[5/2 - 5*x]/Sqrt[3 + 5*x]] - 326717*Sqrt[7]*ArcTan[Sqrt[1 - 2*x]/(Sqrt[7]*Sqrt[3 + 5*x])])/95256

Maple [A] (verified)

Time = 1.15 (sec) , antiderivative size = 142, normalized size of antiderivative = 0.83

method	result	size
risch	\(\frac {\left (-1+2 x \right ) \sqrt {3+5 x}\, \left (75600 x^{3}+286791 x^{2}+275022 x +78416\right ) \sqrt {\left (1-2 x \right ) \left (3+5 x \right )}}{4536 \left (2+3 x \right )^{3} \sqrt {-\left (-1+2 x \right ) \left (3+5 x \right )}\, \sqrt {1-2 x}}+\frac {\left (-\frac {575 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )}{486}+\frac {326717 \sqrt {7}\, \arctan \left (\frac {9 \left (\frac {20}{3}+\frac {37 x}{3}\right ) \sqrt {7}}{14 \sqrt {-90 \left (\frac {2}{3}+x \right )^{2}+67+111 x}}\right )}{190512}\right ) \sqrt {\left (1-2 x \right ) \left (3+5 x \right )}}{\sqrt {1-2 x}\, \sqrt {3+5 x}}\)	\(142\)
default	\(\frac {\sqrt {1-2 x}\, \sqrt {3+5 x}\, \left (8821359 \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right ) x^{3}-6085800 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right ) x^{3}[phone] \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right ) x^{2}-12171600 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right ) x^{2}-3175200 x^{3} \sqrt {-10 x^{2}-x +3}[phone] \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right ) x -8114400 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right ) x -12045222 x^{2} \sqrt {-10 x^{2}-x +3}+2613736 \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right )-1803200 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )-11550924 x \sqrt {-10 x^{2}-x +3}-3293472 \sqrt {-10 x^{2}-x +3}\right )}{190512 \sqrt {-10 x^{2}-x +3}\, \left (2+3 x \right )^{3}}\)	\(270\)

[In]

int((1-2*x)^(3/2)*(3+5*x)^(5/2)/(2+3*x)^4,x,method=_RETURNVERBOSE)

[Out]

1/4536*(-1+2*x)*(3+5*x)^(1/2)*(75600*x^3+286791*x^2+275022*x+78416)/(2+3*x)^3/(-(-1+2*x)*(3+5*x))^(1/2)*((1-2*
x)*(3+5*x))^(1/2)/(1-2*x)^(1/2)+(-575/486*10^(1/2)*arcsin(20/11*x+1/11)+326717/190512*7^(1/2)*arctan(9/14*(20/
3+37/3*x)*7^(1/2)/(-90*(2/3+x)^2+67+111*x)^(1/2)))*((1-2*x)*(3+5*x))^(1/2)/(1-2*x)^(1/2)/(3+5*x)^(1/2)

Fricas [A] (verification not implemented)

none

Time = 0.24 (sec) , antiderivative size = 161, normalized size of antiderivative = 0.94 \[ \int \frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{(2+3 x)^4} \, dx=-\frac {326717 \, \sqrt {7} {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )} \arctan \left (\frac {\sqrt {7} {\left (37 \, x + 20\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{14 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) - 225400 \, \sqrt {10} {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )} \arctan \left (\frac {\sqrt {10} {\left (20 \, x + 1\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) + 42 \, {\left (75600 \, x^{3} + 286791 \, x^{2} + 275022 \, x + 78416\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{190512 \, {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )}} \]

[In]

integrate((1-2*x)^(3/2)*(3+5*x)^(5/2)/(2+3*x)^4,x, algorithm="fricas")

[Out]

-1/190512*(326717*sqrt(7)*(27*x^3 + 54*x^2 + 36*x + 8)*arctan(1/14*sqrt(7)*(37*x + 20)*sqrt(5*x + 3)*sqrt(-2*x
+ 1)/(10*x^2 + x - 3)) - 225400*sqrt(10)*(27*x^3 + 54*x^2 + 36*x + 8)*arctan(1/20*sqrt(10)*(20*x + 1)*sqrt(5*
x + 3)*sqrt(-2*x + 1)/(10*x^2 + x - 3)) + 42*(75600*x^3 + 286791*x^2 + 275022*x + 78416)*sqrt(5*x + 3)*sqrt(-2
*x + 1))/(27*x^3 + 54*x^2 + 36*x + 8)

Sympy [F]

\[ \int \frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{(2+3 x)^4} \, dx=\int \frac {\left (1 - 2 x\right )^{\frac {3}{2}} \left (5 x + 3\right )^{\frac {5}{2}}}{\left (3 x + 2\right )^{4}}\, dx \]

[In]

integrate((1-2*x)**(3/2)*(3+5*x)**(5/2)/(2+3*x)**4,x)

[Out]

Integral((1 - 2*x)**(3/2)*(5*x + 3)**(5/2)/(3*x + 2)**4, x)

Maxima [A] (verification not implemented)

none

Time = 0.31 (sec) , antiderivative size = 161, normalized size of antiderivative = 0.94 \[ \int \frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{(2+3 x)^4} \, dx=\frac {865}{2646} \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}} - \frac {{\left (-10 \, x^{2} - x + 3\right )}^{\frac {5}{2}}}{21 \, {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )}} + \frac {173 \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {5}{2}}}{588 \, {\left (9 \, x^{2} + 12 \, x + 4\right )}} + \frac {34805}{5292} \, \sqrt {-10 \, x^{2} - x + 3} x - \frac {575}{486} \, \sqrt {10} \arcsin \left (\frac {20}{11} \, x + \frac {1}{11}\right ) + \frac {326717}{190512} \, \sqrt {7} \arcsin \left (\frac {37 \, x}{11 \, {\left | 3 \, x + 2 \right |}} + \frac {20}{11 \, {\left | 3 \, x + 2 \right |}}\right ) - \frac {152917}{31752} \, \sqrt {-10 \, x^{2} - x + 3} + \frac {2507 \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}}}{3528 \, {\left (3 \, x + 2\right )}} \]

[In]

integrate((1-2*x)^(3/2)*(3+5*x)^(5/2)/(2+3*x)^4,x, algorithm="maxima")

[Out]

865/2646*(-10*x^2 - x + 3)^(3/2) - 1/21*(-10*x^2 - x + 3)^(5/2)/(27*x^3 + 54*x^2 + 36*x + 8) + 173/588*(-10*x^
2 - x + 3)^(5/2)/(9*x^2 + 12*x + 4) + 34805/5292*sqrt(-10*x^2 - x + 3)*x - 575/486*sqrt(10)*arcsin(20/11*x + 1
/11) + 326717/190512*sqrt(7)*arcsin(37/11*x/abs(3*x + 2) + 20/11/abs(3*x + 2)) - 152917/31752*sqrt(-10*x^2 - x
+ 3) + 2507/3528*(-10*x^2 - x + 3)^(3/2)/(3*x + 2)

Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 404 vs. \(2 (129) = 258\).

Time = 0.58 (sec) , antiderivative size = 404, normalized size of antiderivative = 2.36 \[ \int \frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{(2+3 x)^4} \, dx=\frac {326717}{1905120} \, \sqrt {70} \sqrt {10} {\left (\pi + 2 \, \arctan \left (-\frac {\sqrt {70} \sqrt {5 \, x + 3} {\left (\frac {{\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{140 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}\right )\right )} - \frac {575}{486} \, \sqrt {10} {\left (\pi + 2 \, \arctan \left (-\frac {\sqrt {5 \, x + 3} {\left (\frac {{\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{4 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}\right )\right )} - \frac {10}{81} \, \sqrt {5} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} - \frac {11 \, {\left (2463 \, \sqrt {10} {\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{5} + 1767360 \, \sqrt {10} {\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{3} + 377652800 \, \sqrt {10} {\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}\right )}}{756 \, {\left ({\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{2} + 280\right )}^{3}} \]

[In]

integrate((1-2*x)^(3/2)*(3+5*x)^(5/2)/(2+3*x)^4,x, algorithm="giac")

[Out]

326717/1905120*sqrt(70)*sqrt(10)*(pi + 2*arctan(-1/140*sqrt(70)*sqrt(5*x + 3)*((sqrt(2)*sqrt(-10*x + 5) - sqrt
(22))^2/(5*x + 3) - 4)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))) - 575/486*sqrt(10)*(pi + 2*arctan(-1/4*sqrt(5*x
+ 3)*((sqrt(2)*sqrt(-10*x + 5) - sqrt(22))^2/(5*x + 3) - 4)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))) - 10/81*sqr
t(5)*sqrt(5*x + 3)*sqrt(-10*x + 5) - 11/756*(2463*sqrt(10)*((sqrt(2)*sqrt(-10*x + 5) - sqrt(22))/sqrt(5*x + 3)
- 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))^5 + 1767360*sqrt(10)*((sqrt(2)*sqrt(-10*x + 5) - sqrt
(22))/sqrt(5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))^3 + 377652800*sqrt(10)*((sqrt(2)*s
qrt(-10*x + 5) - sqrt(22))/sqrt(5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22))))/(((sqrt(2)*s
qrt(-10*x + 5) - sqrt(22))/sqrt(5*x + 3) - 4*sqrt(5*x + 3)/(sqrt(2)*sqrt(-10*x + 5) - sqrt(22)))^2 + 280)^3

Mupad [F(-1)]

Timed out. \[ \int \frac {(1-2 x)^{3/2} (3+5 x)^{5/2}}{(2+3 x)^4} \, dx=\int \frac {{\left (1-2\,x\right )}^{3/2}\,{\left (5\,x+3\right )}^{5/2}}{{\left (3\,x+2\right )}^4} \,d x \]

[In]

int(((1 - 2*x)^(3/2)*(5*x + 3)^(5/2))/(3*x + 2)^4,x)

[Out]

int(((1 - 2*x)^(3/2)*(5*x + 3)^(5/2))/(3*x + 2)^4, x)